Thursday, March 17, 2011

Unit 10 Day 3

Today was another CLASSIC day in Mr. H's class. We started by lighting some methane on fire. No biggie. Not that surprising knowing of all the other crazy stuff we've done in this class. Anyways, After that emotional beginning of class, we began to work of some pages in our parquetes.
We began with page 1 number 4. This was a beginning to the mathematical part of this chapter. The main lesson of this day in class was using the equation for molarity which is

MOLARITY = MOLES SOLUTE/LITERS SOLUTION
(molarity=# moles solute per Liter of solution)
So we began with part a. This mainly was made of plugging the numbers into the formula above and then writing it down.
The answers for this section were
a. 2
b. 4
d. 1
f. 1
g. .05
h. 1.5
i. 6
j. .25

^poorly lettered

Next was a new piece of information that stated that the mass of the solute can be related to the mass of solute by the molar mass. We used this in the next problem on the back of page 1 AKA page 2. This page worked on what was previously done in number 4 but added a new element. This was the Mass of solute. All that was needed to get this value was finding the molar mass of the solute and then multiplying by the # of moles.

The Tables answers when like this
a. .5M 1 mol 2 L 40 g
b. 1.5M 3 Mol 2 L 120 g
c. .25 M .5 mol 2 L 20 g
d. .5 M .05 mol .1 L .85g
e. .425 .85 mol 2 L 20 g
f. 2 M 2 mol 1 L 34 g
g. .125 M .5 mol 4 L 8.5 g

we used the rest of the period on a Lab.
That was it
YAY
And now its friday
its the day after thursday
and saturdays after it

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