We started class today by looking over Emma’s blog from yesterday. After that, we turned to page 15 of our packets and continued where we left off on Tuesday. Mr. H introduced the terms saturated, unsaturated, and super saturated to us. To find out which of the following a molecule is, it is necessary to refer to the Solubility Chart. If it is on the line, it is saturated. If it is below the line, it is unsaturated. Lastly, if it is over the line, it is super saturated. We used this information to complete numbers 5 and 6 on page 16. The answers are as follows:
5. a. S
b. US
c. SS
d. SS
e. US
f. S
g. SS
h. S
i. US
6. a.
b. S
c. SS
d. SS
e. SS
f. S
g. US
After completing those pages, we “took a break” with a YouTube video. The video was very funny and was relevant to what we are learning now. We then tried to do the demo from yesterday, but, unfortunatley, it didn’t work. However, it was still interesting to watch.
Next, we turned to page 1 and Mr. H told us why this unit was so different than the past few we've done....because it has math! He then explained the term “concentration” to us. Concentration describes the amount of solute per amount of solvent in any solution. To make this simpler it is: solute/solvent or solute/solution. With this information, we did problems 2 and 3.
In 2, we looked at the examples to see if it represents the definition we just learned. The answers are as follows:
2. a. Ex
b. Ex
c. Non
d. Ex
e. Non
f. Ex
g. Ex
In 3, we ranked the solutions in order from most concentrated to least concentrated. The answers were C>D>B>A. We figured this out by looking at the amount of white space in the picture.
Today’s homework is to do WebAssigns, although there are none due Thursday. That’s all!
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