Unit 12,Day 2

In today’s class, we started out by going over Chapter 4.3 and Chapter 13.1 Reading Sheet, found on page 23 of your unit packet. The answers are as follows:
1. C
2. D
3. True, False, False, True, True
4. D
5. A
6. B
7. A, A, A
8. B
9. A, B
10. False because some substances are amphiprotic
11. Amphiprotic means a proton could either be lost or gained, like with H2O, which can become H3O+ or OH-
12. A, A, B
13. B, C

Then we went over Kon’s blog from Monday, which was about the first day of unit 12.
Next, we began learning about Bronsted and Lowry. They said that you can’t have an acid without having a base. This idea is different than what we learned on Monday, where you would have just split the H from its anion, so keep that in mind.
Then we did problem 6 on page 2. Keep in mind the acid is the proton donator and the base is the proton acceptor.
a. HCN(aq) + H2O(l)  CN- (aq) + H3O+(aq)
b. HF(aq) + H2O(l)  F- (aq) + H3O+(aq)
c. HNO2(aq) + H2O(l)  NO2-(aq) + H3O+(aq)
The H3O+ is called the “Hydronium Ion”
d. *Now we are working with BASES! This means that the base GAINS a proton.
NH3(aq) + H2O(l)  NH4+(aq) + OH-(aq)
C5H5N(aq) + H20(l)  C5H6N+(aq) + OH-(aq)

Next we did a few problems on page 3. Keep in mind that Acids donate protons and Bases accepts protons.
Here is the general equation used for an acid-base reaction.
HA + B  A- BH+
(acid) (base) (conjugate base) (conjugate acid)

Note that “the reaction of an acid with a base changes the acid into a conjugate base and changes the base into a conjugate acid.”
a. B, A, CA, CB
b. A, B, CB, CA
f. A, B, CB, CA
g. B, A, CA, CB
F and G are “zingers”. Because HCO3- is and Acid in part F, you would expect it to be an Acid in part G as well. This however is not true, and you have to always look to see what is giving away the proton and what is receiving it.
We ended class by doing Lab AB1.